Senate Minority Leader Chuck Schumer said he agreed with President-elect Joe Biden’s plan to give transgender students access to sports, bathrooms, and locker rooms of their gender choice. “I agree with the decision, and I know he will check things out thoroughly legally,” Schumer told a reporter who asked if the President-elect has the ability to do this and whether he agreed with the decision. Well, checking things out thoroughly might be problematic for ole Joe. This could be done legally, or it could be done illegally. President Obama attempted to ignite the bathroom wars by saying transgendered people can use any bathroom they want through memoranda. This, of course, had no teeth at all. Biden could go this route, which would be largely ceremonial, or he could allow the Department of Education to issue a regulation. This would be extremely disrespectful of the wishes of most Americans, and may or not be legal. The best, and most constitutional, way to handle it would be through legislation, but this would mean the federal government was actually listening to people. I’m not holding my breath on that one. Here’s the truth. A transgendered bathroom bill is not at the top of most Americans’ concerns right now. According to a 2019 study by Metro Weekly, “Less than one-third of Americans support allowing trans athletes to compete based on their gender identity.” I don’t want the government forcing young female boxers to fight men, and I definitely don’t want them to have to change in the locker room with one. Biden and Schumer are not fighting for what a majority of Americans want. They are pandering to their radical base and will put students in danger with ridiculous identity politics. This is not a good sign of things to come for this administration. Hat Tip: DISRN, Metro Weekly Image Credit: PXHere Leave a Reply Cancel ReplyYour email address will not be published.CommentName* Email* Website Save my name, email, and website in this browser for the next time I comment. Please enter an answer in digits:two × 3 = Δ